[solved]Cut a Number out of a curl - string in a shell script

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Okay hey I need your help!

I playing aorund with the Arest library on my Arduino.

I find out how I can read the data of my DHT22 over Http.
If I open http://192.168.1.10/humidity I get this string:

{"humidity": 27, "id": "008", "name": "dapper_drake", "connected": true}
then I tried to use the the script of leader 21: Sunrise and Sunset device via shellsensor plugin

# Aresttemp.sh


temperatur=$(curl -s http://192.168.1.10/temperature | grep temperature | awk -F\" '{print $2}'|{ date -f - +%R; })
luftfeuchte=$(curl -s http://192.168.1.10/humidity | grep humidity | awk -F\" '{print $4}'|{ date -f - +%R; })

echo "Temperatur $temperatur C, Luftfeuchtigkeit $luftfeuchte %" 

But there is one problem, I don´t know what I have to change to extract only the first number?

I hope you understand my problem and can help me.
thank u

I’m not sure I understood you correctly, but if, using the example from above, you want to extract only the “27” from your line, here’s what you’ll need to do:
curl -s http://192.168.1.10/humidity | sed "s/[,].*//" | sed 's/{humidity:\ //'

Okay it´s the right way! but now it prints out:
Temperatur {"temperature": 20 C, Luftfeuchtigkeit {"humidity": 26 %

now is the question is, who to remove the {"temperature": and the {"humidity":

# Aresttemp.sh


temperatur=$(curl -s http://192.168.1.10/temperature | sed "s/[,].*//" | sed 's/{temperature:\ //")
luftfeuchte=$(curl -s http://192.168.1.10/humidity | sed "s/[,].*//" | sed 's/{humidity:\ //")

echo "Temperatur $temperatur C, Luftfeuchtigkeit $luftfeuchte %" ```

Ah great the Shell work! we forgot the " "

# Aresttemp.sh


temperatur=$(curl -s http://192.168.1.10/temperature | sed "s/[,].*//" | sed 's/{"temperature":\ //')
luftfeuchte=$(curl -s http://192.168.1.10/humidity | sed "s/[,].*//" | sed 's/{"humidity":\ //')

echo "Temperatur:$temperatur °C Luftfeuchtigkeit:$luftfeuchte %"